Tutorial to help answer the question
Which of the following genetic crosses would be predicted to give a phenotypic ratio of 9:3:3:1?
Half of the gametes get a dominant S and a dominant Y allele; the other half of the gametes get a recessive s and a recessive y allele.
Both parents produce 25% each of SY, Sy, sY, and sy.
(Review the tutorials for problems #1 and problem #4 if necessary).
Since each Parent produces 4 different combinations of alleles in the gametes, draw a 4 square by 4 square punnett square.
List the gametes for Parent 1 along one edge of the punnett square.
List the gametes for Parent 2 along one edge of the punnett square.
Fill out the squares with the alleles of Parent 1 .
Fill out the squares with the alleles from Parent 2 .
The result is the prediction of all possible combinations of genotypes for the offspring of the dihybrid cross, SsYy x SsYy.
There are 9 genotypes for spherical, yellow seeded plants. They are:
SSYY (1/16)
SSYy (2/16)
SsYY (2/16)
SsYy (4/16)
Two recessive alleles result in green seeded plants.
There are 2 genotypes for spherical, green seeded plants. They are:
SSyy (1/16)
Ssyy (2/16)
Two recessive s alleles result in dented seeded plants.
There are 2 genotypes for dented, yellow seeded plants. They are:
ssYY (1/16)
ssYy (2/16)
A ssyy plant would be recessive for both traits.
There is only 1 genotypes for dented, green seeded plants. It is:
ssyy (1/16)
A phenotypic ratio of 9:3:3:1 is predicted for the offspring of a SsYy x SsYy dihybrid cross. |
9 spherical, yellow | 3 spherical, green |
3 dented, yellow | 1 dented, green |
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